Question

A) x-4/19=1 б) 3/7+x=11/15

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

Ответ:

а) 1 - это целое тость  19/19 в дробном виде

надо 19/19 + 4/19= 1  4/19

ответ 1 целая и 4/19

и что в этом тяжёлого это же изи примеры

Б) 11\15-3/7=8/15

Answer 3

Let's solve the two equations:

A) $x - \frac{4}{19} = 1$

Step 1: To find the value of $x$, isolate it on one side of the equation. We can do this by adding $\frac{4}{19}$ to both sides of the equation:

$x - \frac{4}{19} + \frac{4}{19} = 1 + \frac{4}{19}$

$x = 1 + \frac{4}{19}$

Step 2: Now, let's find the common denominator of 19, so we can add the fractions on the right side:

$x = \frac{19}{19} + \frac{4}{19}$

$x = \frac{23}{19}$

So, the solution to equation A is $x = \frac{23}{19}$.

B) $\frac{3}{7} + x = \frac{11}{15}$

Step 1: To find the value of $x$, isolate it on one side of the equation. We can do this by subtracting $\frac{3}{7}$ from both sides of the equation:

$\frac{3}{7} + x - \frac{3}{7} = \frac{11}{15} - \frac{3}{7}$

Step 2: Now, let's find the common denominator of 15 and 7, so we can subtract the fractions on the right side:

$\frac{4}{15} + x = \frac{11 \times 7}{15 \times 7} - \frac{3 \times 15}{7 \times 15}$

$\frac{4}{15} + x = \frac{77}{105} - \frac{45}{105}$

$\frac{4}{15} + x = \frac{32}{105}$

Step 3: Finally, isolate $x$ on one side by subtracting $\frac{4}{15}$ from both sides:

$x = \frac{32}{105} - \frac{4}{15}$

Step 4: Find the common denominator of 105 and 15, so we can subtract the fractions on the right side:

$x = \frac{32 \times 3}{105 \times 3} - \frac{4 \times 7}{15 \times 7}$

$x = \frac{96}{315} - \frac{28}{105}$

Step 5: Now, find the common denominator of 315, so we can subtract the fractions on the right side:

$x = \frac{96}{315} - \frac{28 \times 3}{105 \times 3}$

$x = \frac{96}{315} - \frac{84}{315}$

Step 6: Combine the fractions on the right side:

$x = \frac{96 - 84}{315}$

$x = \frac{12}{315}$

Step 7: Reduce the fraction to its simplest form:

$x = \frac{4}{105}$

So, the solution to equation B is $x = \frac{4}{105}$.

Therefore, the solutions to the two equations are:

A) $x = \frac{23}{19}$