Question

Найти f(1/2, 3) и f(1, -1) f(x.y)=ху+х/у

Answer 1

Ответ:

f(1/2,3)=5/3

f(1,-1)=-2

Пошаговое объяснение:

f(1/2,3)=1/2*3+1/2:3=3/2+1/6=5/3=1 2/3

f(1,-1)=1*(-1)+1:(-1)=-1+(-1)=-1-1=2

Answer 2

Ответ:

f(1/2,3)=5/3

f(1,-1)=-2

Пошаговое объяснение:

f(1/2,3)=1/2*3+1/2:3=3/2+1/6=5/3=1 2/3

f(1,-1)=1*(-1)+1:(-1)=-1+(-1)=-1-1=2

Answer 3

To find the values of f(1/2, 3) and f(1, -1) for the given function f(x,y) = xy + x/y, simply substitute the given values of x and y into the function:

1. f(1/2, 3): f(x, y) = xy + x/y f(1/2, 3) = (1/2) * 3 + (1/2) / 3 f(1/2, 3) = 3/2 + 1/6 f(1/2, 3) = 9/6 + 1/6 f(1/2, 3) = 10/6 f(1/2, 3) = 5/3

2. f(1, -1): f(x, y) = xy + x/y f(1, -1) = 1 * (-1) + 1 / (-1) f(1, -1) = -1 - 1 f(1, -1) = -2

So, the values of f(1/2, 3) and f(1, -1) are:

f(1/2, 3) = 5/3 f(1, -1) = -2