Question

1) 3x+4/28=22/7;2) 2 1/7÷=3 1/3x÷1,5​

Answer 1

Ответ:

первое и второе

Answer 2

Let's solve each of the given equations step by step:

1. Solve for x in the equation 3x + 4/28 = 22/7:

First, let's get rid of the fraction by multiplying both sides of the equation by 28 to eliminate the denominator: 3x + 4/28 = 22/7

Multiply both sides by 28: 28 * (3x + 4/28) = 28 * (22/7)

Simplify: 3x * 28 + 4 = 88

Now, subtract 4 from both sides: 3x * 28 = 84

Divide both sides by 28: 3x = 84 / 28

Simplify: 3x = 3

Divide both sides by 3: x = 1

So, the solution for the first equation is x = 1.

2. Solve the equation 2 1/7 ÷ 3 = 1 1/3x ÷ 1.5:

Let's first convert the mixed numbers into improper fractions: 2 1/7 = 15/7 1 1/3 = 4/3

Now, rewrite the equation: (15/7) ÷ 3 = (4/3)x ÷ 1.5

Simplify: (15/7) * (1/3) = (4/3)x * (1/1.5)

Multiply both sides by 7 to eliminate the denominator in the left-hand side: 15 * (1/3) = (4/3)x * (1/1.5) * 7

Simplify: 5 = (4/3)x * (7/1.5)

Multiply the fractions on the right-hand side: 5 = (28/4.5)x

Now, isolate x by dividing both sides by (28/4.5): x = 5 / (28/4.5)

To divide by a fraction, multiply by its reciprocal: x = 5 * (4.5/28)

Simplify: x = 0.80357142857

Rounded to a few decimal places, x ≈ 0.804.

So, the solution for the second equation is x ≈ 0.804.