Question

При каких значениях x трёхчлен x2+6x−35 принимает значение, равное 1?​

Answer 1

Ответ:

176

Пошаговое объяснение:

Answer 2

To find the values of x for which the quadratic expression $x^2 + 6x - 35$ takes the value of 1, we can set the expression equal to 1 and then solve for x.

So, the equation is: $x^2 + 6x - 35 = 1$

Now, let's bring all terms to one side to get a quadratic equation in standard form:

$x^2 + 6x - 36 = 0$

Now, we can either factor the quadratic or use the quadratic formula to find the values of x. In this case, let's factor the quadratic equation:

$(x + 9)(x - 4) = 0$

Now, set each factor equal to zero and solve for x:

1. $x + 9 = 0$ $x = -9$

2. $x - 4 = 0$ $x = 4$

So, the quadratic expression $x^2 + 6x - 35$ takes the value of 1 when $x = -9$ or $x = 4$.