Question

1) -3(3y+4)+4(2y-1)=0 2) 0.3(5x-7)=3(0.2x+3.2) Решите пожалуйста уравнения без сокращений и тд.

Answer 1

Ответ:

1.    $-3(3y+4)+4(2y-1)=0$

$-9y-12+8y-4=0$

$-y-16=0$

$-y=16$

$y=-16$

2.   $0,3(5x-7)=3(0,2x+3,2)$

$1,5x - 2,1 = 0,6x +9,6$        

$1,5x -0,6x = 2,1 +9,6$

$0,9x = 11,7$      

$x = 13$

Answer 2

1. -3(3y+4) + 4(2y-1) = 0

Let's simplify the equation step by step:

First, distribute the -3 and 4:

-9y - 12 + 8y - 4 = 0

Combine like terms:

(-9y + 8y) + (-12 - 4) = 0

-y - 16 = 0

Next, isolate the variable by adding 16 to both sides:

-y = 16

Finally, multiply both sides by -1 to solve for y:

y = -16

Therefore, the solution to the equation is y = -16.

2. 0.3(5x-7) = 3(0.2x+3.2)

Let's simplify the equation step by step:

First, distribute the 0.3 and 3:

1.5x - 2.1 = 0.6x + 9.6

Next, move all the terms with x to one side and the constants to the other side:

1.5x - 0.6x = 9.6 + 2.1

0.9x = 11.7

Finally, divide both sides by 0.9 to solve for x:

x = 11.7 / 0.9

x ≈ 13

Therefore, the solution to the equation is x ≈ 13.