Question

1) 3(x − 2) =5 x + 2 2) 5 − 2(x − 1) = 14 − 5x 3) (4x + 1) − (11x + 3) = 5 4) 3,4 + 2y = 7(y − 2,3) 5) 0,2(9 − 3y) = 2,3 − 0,7(y − 6) 6) 2/3(1/3x-1/2)=4x+ 2 1/2. ДАЮ 15 БАЛЛОВ!!!

Answer 1

Решение указано на фото

Answer 2

To solve each of these equations, I'll go through them one by one:

1. 3(x − 2) = 5x + 2

Expand the expression: 3x - 6 = 5x + 2

Now, isolate the variable x on one side of the equation: 3x - 5x = 2 + 6 -2x = 8

Finally, solve for x: x = 8 / -2 x = -4

2. 5 − 2(x − 1) = 14 − 5x

Expand the expression: 5 - 2x + 2 = 14 - 5x

Combine like terms: 7 - 2x = 14 - 5x

Now, isolate the variable x on one side of the equation: -2x + 5x = 14 - 7 3x = 7

Finally, solve for x: x = 7 / 3

3. (4x + 1) − (11x + 3) = 5

Remove the parentheses: 4x + 1 - 11x - 3 = 5

Combine like terms: 4x - 11x + 1 - 3 = 5

Simplify: -7x - 2 = 5

Now, isolate the variable x on one side of the equation: -7x = 5 + 2 -7x = 7

Finally, solve for x: x = 7 / -7 x = -1

4. 3.4 + 2y = 7(y − 2.3)

Distribute on the right side: 3.4 + 2y = 7y - 16.1

Now, isolate the variable y on one side of the equation: 2y - 7y = -16.1 - 3.4 -5y = -19.5

Finally, solve for y: y = -19.5 / -5 y = 3.9

5. 0.2(9 − 3y) = 2.3 − 0.7(y − 6)

Distribute on the left side: 1.8 - 0.6y = 2.3 - 0.7y + 4.2

Combine like terms: 1.8 - 2.3 = -0.7y + 0.6y + 4.2

Simplify: -0.5 = -0.1y + 4.2

Now, isolate the variable y on one side of the equation: -0.1y = -0.5 - 4.2 -0.1y = -4.7

Finally, solve for y: y = -4.7 / -0.1 y = 47

6. (2/3)(1/3x - 1/2) = 4x + 2.5

First, simplify the left side of the equation: (2/3)(1/3x - 1/2) = (2/9)x - 1/3

Now, isolate the variable x on one side of the equation: (2/9)x = 4x + 2.5 + 1/3 (2/9)x = 4x + 2.8333

Next, bring all terms with x to one side of the equation: (2/9)x - 4x = 2.8333

Now, find a common denominator for (2/9) and 4: (2/9)x - (36/9)x = 2.8333

Combine like terms: -(34/9)x = 2.8333

Finally, solve for x: x = 2.8333 / (-(34/9)) x = -0.236

Please double-check my calculations to ensure accuracy. If there are any issues or questions, feel free to ask!