Question

1) 0,3(6-3у)=4,5-0,8(у-9)2) 0,5х-0,3х=23) 0,2/(х+3)=0,7 /(х-2)

Answer 1

Ответ:

3-й не поместился

Пошаговое объяснение:

• 1)0,3(6-3y)=4,5-0,8(y-9)          0,5x-0,3x=2  → 0,2x=2  → x=10                          

1,8-0,9y=4,5-0,8y+7,2

1,8-0,9y=11,7-0,8y

-0,9y+0,8y=11,7-1,8

-0,1y=9,9

y=-99

Answer 2

It looks like you've provided three equations. Let's solve them step by step:

Equation 1: $0.3(6-3y) = 4.5 - 0.8(y-9)$

First, distribute the numbers and variables: $1.8 - 0.9y = 4.5 - 0.8y + 7.2$

Combine like terms: $-0.9y + 0.8y = 4.5 + 7.2 - 1.8$ $0.1y = 9.9$

Now, solve for $y$: $y = \frac{9.9}{0.1} = 99$

Equation 2: $0.5x - 0.3x = 2$

Combine like terms: $0.2x = 2$

Solve for $x$: $x = \frac{2}{0.2} = 10$

Equation 3: $\frac{0.2}{x+3} = \frac{0.7}{x-2}$

Cross-multiply to get rid of fractions: $0.2(x-2) = 0.7(x+3)$

Distribute and simplify: $0.2x - 0.4 = 0.7x + 2.1$

Subtract $0.2x$ from both sides: $-0.4 = 0.5x + 2.1$

Subtract $2.1$ from both sides: $-2.5 = 0.5x$

Now, solve for $x$: $x = \frac{-2.5}{0.5} = -5$

So, the solutions are: Equation 1: $y = 99$ Equation 2: $x = 10$ Equation 3: $x = -5$