Question

1)2(8x-7)=6-4(5-4x). 2)0,4(6-4x)=0,5(7-3x)-1,9. 3)3(x+5)=x+2(x+9)

Answer 1

Ответ:

16x-14=6-20-16x

32x=6-6

x=0

2,4-1,6x=3,5-1,5x-1,9

0,1x=-0,8

x=-8

3x+15=x+2x+18

3x-3x=3

решения нет

Пошаговое объяснение:

Answer 2

Let's solve each equation step by step:

1. 2(8x - 7) = 6 - 4(5 - 4x)

First, distribute the constants and variables within the parentheses: 16x - 14 = 6 - 20 + 16x

Now, let's isolate the variable (x) by moving the constants to the other side: 16x - 16x = 6 - 20 + 14 0 = 0

The result is 0 = 0. This equation is true for all values of x. In other words, it's an identity, meaning the solution is any real number.

2. 0.4(6 - 4x) = 0.5(7 - 3x) - 1.9

First, distribute the constants and variables within the parentheses: 2.4 - 1.6x = 3.5 - 1.5x - 1.9

Now, let's simplify the equation by combining like terms: -1.6x + 1.6x = 3.5 - 1.9 - 2.4 0 = -0.8

The result is 0 = -0.8. This equation is not true for any value of x. In other words, there is no solution that satisfies this equation.

3. 3(x + 5) = x + 2(x + 9)

First, distribute the constants and variables within the parentheses: 3x + 15 = x + 2x + 18

Now, let's simplify the equation by combining like terms: 3x + 15 = 3x + 18

Subtract 3x from both sides to isolate the constant: 3x - 3x + 15 = 3x - 3x + 18 15 = 18

The result is 15 = 18. This equation is not true for any value of x. In other words, there is no solution that satisfies this equation.