Question

77/90-(4/5×11/18+19/90) 2 23/40-(1 3/8+2/5)

Answer 1

Ответ:

Пошаговое объяснение:

Answer 2

To solve the given expressions, let's break down the calculations step by step:

1. $\frac{77}{90} - \left( \frac{4}{5} \times \frac{11}{18} + \frac{19}{90} \right)$

First, let's calculate the values inside the parentheses:

$\frac{4}{5} \times \frac{11}{18} = \frac{44}{90}$

Now add this to $\frac{19}{90}$:

$\frac{44}{90} + \frac{19}{90} = \frac{63}{90} = \frac{7}{10}$

Now subtract this from $\frac{77}{90}$:

$\frac{77}{90} - \frac{7}{10} = \frac{77}{90} - \frac{63}{90} = \frac{14}{90} = \frac{7}{45}$

So, $\frac{77}{90} - \left( \frac{4}{5} \times \frac{11}{18} + \frac{19}{90} \right) = \frac{7}{45}$

2. $2\frac{23}{40} - \left( 1\frac{3}{8} + \frac{2}{5} \right)$

First, convert the mixed numbers to improper fractions:

$2\frac{23}{40} = \frac{2 \cdot 40 + 23}{40} = \frac{83}{40}$

$1\frac{3}{8} = \frac{1 \cdot 8 + 3}{8} = \frac{11}{8}$

Now add this to $\frac{2}{5}$:

$\frac{11}{8} + \frac{2}{5}$

To add these fractions, find a common denominator, which is $8 \times 5 = 40$:

$\frac{11}{8} \cdot \frac{5}{5} + \frac{2}{5} \cdot \frac{8}{8} = \frac{55}{40} + \frac{16}{40} = \frac{71}{40}$

Now subtract this from $\frac{83}{40}$:

$\frac{83}{40} - \frac{71}{40} = \frac{12}{40} = \frac{3}{10}$

So, $2\frac{23}{40} - \left( 1\frac{3}{8} + \frac{2}{5} \right) = \frac{3}{10}$ 0 0