Вопрос задан 07.07.2023 в 21:44. Предмет Математика. Спрашивает Делаев Гияс.

1) x-8/3=5x-1/5 2) |4-5x|=6 3) (0,8-0,2x)(1/3x+12)=0

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Отвечает Андреева Елизавета.

Пошаговое объяснение:

Все показано на рисунке выше


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Отвечает нейросеть ChatGpt. Будьте внимательны, ответы нейросети могут содержать ошибочные или выдуманные данные.

Sure! Let's solve each equation step by step:

  1. x - 8/3 = 5x - 1/5

To solve this equation, we'll first simplify the equation by clearing the fractions. We can do this by multiplying every term by the least common multiple (LCM) of the denominators, which is 15 in this case. Multiply both sides of the equation by 15:

15(x) - 15(8/3) = 15(5x) - 15(1/5)

15x - 40 = 75x - 3

Next, let's combine like terms:

15x - 75x = -3 + 40

-60x = 37

To isolate x, divide both sides by -60:

x = 37 / -60

Simplifying the fraction gives:

x = -37 / 60

So the solution to the equation is x = -37 / 60.

  1. |4 - 5x| = 6

The absolute value equation can be rewritten as two separate equations:

4 - 5x = 6 or 4 - 5x = -6

For the first equation, solve for x:

4 - 5x = 6

Subtract 4 from both sides:

-5x = 6 - 4

-5x = 2

Divide both sides by -5 (remember to flip the inequality when dividing by a negative number):

x = 2 / -5

Simplifying the fraction gives:

x = -2/5

For the second equation, solve for x:

4 - 5x = -6

Subtract 4 from both sides:

-5x = -6 - 4

-5x = -10

Divide both sides by -5:

x = -10 / -5

Simplifying the fraction gives:

x = 2

So the solutions to the equation are x = -2/5 and x = 2.

  1. (0,8 - 0,2x)(1/3x + 12) = 0

To find the solutions, we'll set each factor equal to zero:

0,8 - 0,2x = 0 or 1/3x + 12 = 0

For the first equation, solve for x:

0,8 - 0,2x = 0

Subtract 0.8 from both sides:

-0,2x = -0,8

Divide both sides by -0.2:

x = -0,8 / -0,2

Simplifying the fraction gives:

x = 4

For the second equation, solve for x:

1/3x + 12 = 0

Subtract 12 from both sides:

1/3x = -12

Multiply both sides by 3:

x = -12 * 3

Simplifying the expression gives:

x = -36

So the solutions to the equation are x = 4 and x = -36.

I used commas instead of decimal points based on the format you provided, but usually, decimal points are used in mathematical notation.

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