Question

1.5(x+2y)-4(y-3x)-13.5=0 2(y-3x)+2.5(x+2y)+3,5=0

Answer 1

Відповідь:

1)x=y*2/27+1, y=R

2)y=x-1/2, x=R

Покрокове пояснення:

1)

1.5x+3y-4y+12x-13.5=0

13.5x-y-13.5=0

13.5=y+13.5

x=y*2/27+1, y=R

2)

2y-6x+2.5x+5y+3.5=0

7y-3.5x+3.5=0

7y=3.5x-3.5

y=3.5x/7-0.5

y=7x/2/7-1/2

y=x/2-1/2

y=x-1/2

Answer 2

It looks like you have a system of two linear equations with two variables. The equations are:

Equation 1: $1.5(x+2y) - 4(y-3x) - 13.5 = 0$ Equation 2: $2(y-3x) + 2.5(x+2y) + 3.5 = 0$

To solve for the values of $x$ and $y$, we can follow these steps:

Step 1: Distribute the terms within the equations to simplify them. Step 2: Combine like terms. Step 3: Solve one of the equations for one variable and substitute it into the other equation. Step 4: Solve for the remaining variable. Step 5: Substitute the value of the remaining variable back into one of the equations to find the other variable.

Let's go through these steps:

Equation 1: $1.5x + 3y - 4y + 12x - 13.5 = 0$ Simplifying: $13.5x - y - 13.5 = 0$

Equation 2: $2y - 6x + 2.5x + 5y + 3.5 = 0$ Simplifying: $2.5x + 7y - 6x + 3.5 = 0$ $2.5x - 6x + 7y = -3.5$ $-3.5x + 7y = -3.5$

Now we have a system of equations: Equation A: $13.5x - y - 13.5 = 0$ Equation B: $-3.5x + 7y = -3.5$

Let's solve Equation B for $x$: $-3.5x = -3.5 - 7y$ $x = \frac{3.5 + 7y}{3.5}$ $x = 1 + 2y$

Substitute the value of $x$ into Equation A: $13.5(1 + 2y) - y - 13.5 = 0$ $13.5 + 27y - y - 13.5 = 0$ $26y = 0$ $y = 0$

Now that we have $y = 0$, we can substitute this value back into the equation for $x$: $x = 1 + 2(0)$ $x = 1$

So, the solution to the system of equations is $x = 1$ and $y = 0$.