Question

15x^2-10=0 5x^2-162=0

Answer 1

Ответ:

Пошаговое объяснение:

15x^2-10=0

15x^2=10

x^2=2/3

x=+√2/3 или x=-√2/3

5x^2-162=0

5x^2=162

x^2=32,4;

x=+√32,4  или x=-√32,4;

Answer 2

It seems like you have provided two quadratic equations. To solve for the values of 'x' that satisfy these equations, we can use the quadratic formula:

For a quadratic equation in the form of ax^2 + bx + c = 0, the quadratic formula states that:

x = (-b ± √(b^2 - 4ac)) / 2a

Let's solve the given equations:

1. 15x^2 - 10 = 0: Here, a = 15, b = 0, and c = -10. Plugging the values into the quadratic formula:

   x = (0 ± √(0^2 - 4 * 15 * -10)) / (2 * 15) x = ± √(600) / 30 x = ± √(36) / 30 x = ± 6 / 30 x = ± 1/5

   So, the solutions for the first equation are x = 1/5 and x = -1/5.

2. 5x^2 - 162 = 0: Here, a = 5, b = 0, and c = -162. Plugging the values into the quadratic formula:

   x = (0 ± √(0^2 - 4 * 5 * -162)) / (2 * 5) x = ± √(3240) / 10 x = ± √(324) / 10 x = ± 18 / 10 x = ± 9 / 5

   So, the solutions for the second equation are x = 9/5 and x = -9/5.

In summary:

1. Solutions for 15x^2 - 10 = 0 are x = 1/5 and x = -1/5.
2. Solutions for 5x^2 - 162 = 0 are x = 9/5 and x = -9/5.