Question

0,4x+12=-0,16 -2(5-2x)=-14 I2xI+1=6

Answer 1

Ответ:

0,4х=-12-0,16

0,4х=-12,16

х=-30,4

-10-4х=-14

-4х=10-14

-4х=-4

х=1

|2х|+1=6

2х+1=6

2х=-1+6

2х=5

х=2,5

Answer 2

It looks like you've provided a system of three equations. Let's solve them step by step:

Equation 1: 0.4x + 12 = -0.16 Subtract 12 from both sides: 0.4x = -12.16

Divide both sides by 0.4: x = -30.4

Equation 2: -2(5 - 2x) = -14 Distribute the -2 on the left side: -10 + 4x = -14

Add 10 to both sides: 4x = -4

Divide both sides by 4: x = -1

Equation 3: |2x| + 1 = 6 Subtract 1 from both sides: |2x| = 5

Now there are two possible solutions for |2x|:

1. 2x = 5 Divide both sides by 2: x = 2.5

2. -2x = 5 Divide both sides by -2: x = -2.5

So, the possible values of x that satisfy the third equation are x = 2.5 and x = -2.5.

In summary, the solutions for the system of equations are x = -30.4, x = -1, x = 2.5, and x = -2.5.