Question

Y=x^(5)+2x^(4)+x^(3)+1 x0=1 Решите плиз

Answer 1

Пошаговое объяснение:

y'=5x^4+8x^3+3x^2

f' (x0)=5*1^4+8*1^3+3*1^2=5+8+3=16

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Answer 2

To find the solution for $x_0 = 1$ in the equation $y = x^5 + 2x^4 + x^3 + 1$, we can substitute $x = 1$ into the equation and calculate the value of $y$.

Substituting $x = 1$ into the equation, we have:

$y = 1^5 + 2(1)^4 + (1)^3 + 1$ $y = 1 + 2 + 1 + 1$ $y = 5$

Therefore, when $x_0 = 1$, the value of $y$ is 5.