Question

14(2-3)-5(y+4)=2(3y+5)+5y;​

Answer 1

Ответ:

24-42-5y-20=6y+10+5y

-5y-6y-5y=10-24+42+20

-16y=48

y=-3

напиши сначала уравнение а потом все что выше

Answer 2

To solve the equation, follow these steps:

Step 1: Distribute the numbers and variables on both sides of the equation: 14 * 2 - 14 * 3 - 5 * y - 5 * 4 = 2 * 3 * y + 2 * 5 + 5 * y

Simplify both sides: 28 - 42 - 5y - 20 = 6y + 10 + 5y

Step 2: Combine like terms on both sides: -14 - 5y = 11y + 10

Step 3: Get all the y terms on one side by adding 5y to both sides: -14 - 5y + 5y = 11y + 10 + 5y -14 = 16y + 10

Step 4: Subtract 10 from both sides: -14 - 10 = 16y + 10 - 10 -24 = 16y

Step 5: Divide both sides by 16 to solve for y: y = -24 / 16 y = -3/2

So, the solution to the equation is y = -3/2.