Question

-x²+4x-1=0 4x²-10x+5=0

Answer 1

Пошаговое объяснение:

вВ першому равнняні друга стрічка було -2 а в третій стало 2х тому що ми -2-4 столо 2 ому там 2.

Answer 2

It looks like you've provided two quadratic equations:

1. $-x^2 + 4x - 1 = 0$
2. $4x^2 - 10x + 5 = 0$

To solve for $x$ in each of these equations, we can use the quadratic formula:

For a quadratic equation $ax^2 + bx + c = 0$, the solutions for $x$ are given by:

$x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$

Let's solve each of your equations using the quadratic formula:

1. For $-x^2 + 4x - 1 = 0$, here $a = -1$, $b = 4$, and $c = -1$.

   Using the quadratic formula:

   $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ $x = \frac{-4 \pm \sqrt{4^2 - 4(-1)(-1)}}{2(-1)}$ $x = \frac{-4 \pm \sqrt{16 - 4}}{-2}$ $x = \frac{-4 \pm \sqrt{12}}{-2}$ $x = \frac{-4 \pm 2\sqrt{3}}{-2}$

   So, the solutions are: $x = 2 - \sqrt{3}$ and $x = 2 + \sqrt{3}$

2. For $4x^2 - 10x + 5 = 0$, here $a = 4$, $b = -10$, and $c = 5$.

   Using the quadratic formula:

   $x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a}$ $x = \frac{10 \pm \sqrt{(-10)^2 - 4(4)(5)}}{2(4)}$ $x = \frac{10 \pm \sqrt{100 - 80}}{8}$ $x = \frac{10 \pm \sqrt{20}}{8}$ $x = \frac{10 \pm 2\sqrt{5}}{8}$ $x = \frac{5 \pm \sqrt{5}}{4}$

   So, the solutions are: $x = \frac{5 - \sqrt{5}}{4}$ and $x = \frac{5 + \sqrt{5}}{4}$