Question

X^2+6x+8=0 5x^2-8x+3=0

Answer 1

Решается просто через дискриминант

Answer 2

It looks like you've provided two quadratic equations. To solve for the values of x that satisfy these equations, we can use the quadratic formula:

For an equation of the form ax^2 + bx + c = 0, the quadratic formula states:

x = (-b ± √(b^2 - 4ac)) / 2a

Let's solve each equation separately using this formula:

1. x^2 + 6x + 8 = 0 Here, a = 1, b = 6, and c = 8.

   Using the quadratic formula: x = (-6 ± √(6^2 - 4 * 1 * 8)) / (2 * 1) x = (-6 ± √(36 - 32)) / 2 x = (-6 ± √4) / 2 x = (-6 ± 2) / 2

   So, the solutions are: x = (-6 + 2) / 2 = -2 / 2 = -1 x = (-6 - 2) / 2 = -8 / 2 = -4

2. 5x^2 - 8x + 3 = 0 Here, a = 5, b = -8, and c = 3.

   Using the quadratic formula: x = (8 ± √((-8)^2 - 4 * 5 * 3)) / (2 * 5) x = (8 ± √(64 - 60)) / 10 x = (8 ± √4) / 10 x = (8 ± 2) / 10

   So, the solutions are: x = (8 + 2) / 10 = 10 / 10 = 1 x = (8 - 2) / 10 = 6 / 10 = 0.6

Therefore, the solutions for the equations are:

1. x = -1 and x = -4
2. x = 1 and x = 0.6