Question

3(х квадрат 2-2)-3х+7-3(х квадрад2-2х)=0​

Answer 1

Ответ:

Решение на фотографии

Answer 2

To solve the given equation, let's break it down step by step and simplify it:

1. Distribute the constants in the equation: 3(x^2 - 2) - 3x + 7 - 3(x^2 - 2x) = 0

2. Distribute the constants within the parentheses: 3x^2 - 6 - 3x + 7 - 3x^2 + 6x = 0

3. Combine like terms: (3x^2 - 3x^2) + (-3x + 6x) + (-6 + 7) = 0 0x^2 + 3x + 1 = 0

So, the simplified equation is: 3x + 1 = 0

4. Now, solve for x: 3x = -1 x = -1/3

The solution to the equation is x = -1/3.