Question

A) x -2 8/15=3 7/12б)3,45.(2.08-k)=6,21​

Answer 1

Ответ:

99/20 или 4.95 b)0.268

Пошаговое объяснение:

a)x -2 8/15=3 7/12

x=37/12+28/15

x=99/20

b)3.45(2.08-k)=6.21

7.176-3.45x=6.25

-3.45x=6.25-7.176

-3.45x=-0/926

x=463/1725

x=0.268

Answer 2

It looks like you've provided two equations with variables. You'd like to solve for the variable in each equation. Let's solve them step by step:

A) $x - \frac{2}{15} = \frac{3}{4} + \frac{7}{12}$

To solve for $x$, you need to isolate $x$ on one side of the equation:

First, add the fractions on the right side: $\frac{3}{4} + \frac{7}{12} = \frac{9}{12} + \frac{7}{12} = \frac{16}{12}$

Now, subtract $\frac{2}{15}$ from both sides: $x = \frac{16}{12} + \frac{2}{15}$

Find a common denominator for the fractions: $x = \frac{5 \cdot 16}{5 \cdot 12} + \frac{2 \cdot 12}{15 \cdot 12}$ $x = \frac{80}{60} + \frac{24}{180}$

Simplify the fractions: $x = \frac{4}{3} + \frac{1}{15}$ $x = \frac{20}{15} + \frac{1}{15}$ $x = \frac{21}{15}$ $x = \frac{7}{5}$

So, the solution for the equation A is $x = \frac{7}{5}$.

B) $3.45 \cdot (2.08 - k) = 6.21$

To solve for $k$, you need to isolate $k$ on one side of the equation:

Divide both sides of the equation by $3.45$: $\frac{3.45 \cdot (2.08 - k)}{3.45} = \frac{6.21}{3.45}$

Simplify the left side: $2.08 - k = \frac{6.21}{3.45}$

Now, subtract $2.08$ from both sides: $-k = \frac{6.21}{3.45} - 2.08$

Calculate the right side: $-k = 1.8 - 2.08$ $-k = -0.28$

Multiply both sides by -1 to solve for $k$: $k = 0.28$

So, the solution for the equation B is $k = 0.28$.