Question

(a+6)(a-9)>(a+11)(a-14)​

Answer 1

Ответ:

(a+6)x(a-9)^(a+11)+(a-14)

a2-9a+6a-54^a2-14a+11a-154

-9a+6a-54^-14a+11a-154

-3a-54^3a-154

=AER

Answer 2

To solve this inequality, we'll need to expand the expressions on both sides and then simplify the inequality.

Given inequality: (a + 6)(a - 9) > (a + 11)(a - 14)

Let's expand both sides:

Left side: (a + 6)(a - 9) = a^2 - 9a + 6a - 54 = a^2 - 3a - 54 Right side: (a + 11)(a - 14) = a^2 - 14a + 11a - 154 = a^2 - 3a - 154

So, the inequality becomes: a^2 - 3a - 54 > a^2 - 3a - 154

Now, we can subtract a^2 and -3a from both sides to simplify the inequality:

-54 > -154

This is true for all values of 'a'. In other words, the inequality is satisfied for any real value of 'a'.

Therefore, the solution to the inequality (a + 6)(a - 9) > (a + 11)(a - 14) is all real values of 'a'.