Question

3cosx -4sinx cosx =0

Answer 1

Ответ: Не за что)))

Пошаговое объяснение:

Answer 2

Ответ:

Отв:3 соsx

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Answer 3

To solve the equation 3cos(x) - 4sin(x)cos(x) = 0, we can first factor out cos(x) and then apply the zero-product property. Let's go through the steps:

1. Start with the equation: 3cos(x) - 4sin(x)cos(x) = 0.

2. Factor out cos(x): cos(x)(3 - 4sin(x)) = 0.

Now, we have two possibilities:

Case 1: cos(x) = 0 When cos(x) = 0, x can take on values that satisfy cos(x) = 0, such as x = π/2 + πn, where n is an integer.

Case 2: 3 - 4sin(x) = 0 To solve this equation, we need to isolate sin(x): 4sin(x) = 3 sin(x) = 3/4

Now, we can find the values of x that satisfy sin(x) = 3/4. Using inverse sine (arcsin) function, we find two principal solutions between -π/2 and π/2:

x = arcsin(3/4) ≈ 0.8481 (in radians) x = π - arcsin(3/4) ≈ 2.2935 (in radians)

Therefore, the solutions to the equation 3cos(x) - 4sin(x)cos(x) = 0 are: x = π/2 + πn, where n is an integer, x ≈ 0.8481, and x ≈ 2.2935.