Question

999-997+995-993 +..+103 - 101 =

Answer 1

Ответ:

999-997+995-993 +..+103 - 101 =6

Answer 2

It looks like you're trying to calculate the sum of a sequence of numbers. The sequence you've provided seems to consist of consecutive even and odd numbers being added and subtracted alternately. The pattern seems to be:

$999 - 997 + 995 - 993 + \ldots + 103 - 101$

Notice that each even number is followed by its consecutive odd number. To simplify the calculation, you can pair these numbers up and observe that each pair adds up to 2:

$(999 - 997) + (995 - 993) + \ldots + (103 - 101) = 2 + 2 + \ldots + 2$

Now you need to determine how many pairs there are. The numbers start at 999 and end at 103, and the even and odd numbers alternate. So, there are a total of $\frac{999 - 103}{2} + 1$ pairs:

$\frac{999 - 103}{2} + 1 = \frac{896}{2} + 1 = 448 + 1 = 449$

Now, you can calculate the sum:

$\text{Sum} = 449 \times 2 = 898$

So, the result of the given sequence is 898.