Question

A.)3(2b-a)+2(3b-a)=... b.)2a(6a-7b)-3a(5b-2a)=.. c.) 8a^-2a(4a-5b)=... d.) 3(b^ +4b-2)+(2+b)•(-3b)=... ^ - в квадрате • - умножение

Answer 1

Ответ:1)3(2b-a)+2(3b-a)=12b-5a

2)2a(6a-7b)-3a(5b-2a)=18a^2-29a*b

3)8a^-2a(4a-5b)=32a^(-1)-40a^(-2a)*b

4)3(b^+4b-2)+(2+b)•(-3b)=15b+36b*�*�*�+18b^2*�*�*�

Пошаговое объяснение:хз

Answer 2

Ответ:

Пошаговое объяснение:

a.)3(2b-a)+2(3b-a)= 6b - 3a + 6b - 2a = 12b - 5a

b.)2a(6a-7b)-3a(5b-2a)= 12a² - 14ab - 15ab + 6a² = 18a² - 29ab

c.) 8a²-2a(4a-5b)= 8a² - 8a² + 10ab = 10ab

d.) 3(b² +4b-2)+(2+b)•(-3b)= 3b² + 12b - 6 - 6b - 3b² = 6b - 6

Answer 3

a.) Simplifying the expression:
$3(2b-a)+2(3b-a)$

Expand each term within the parentheses and then combine like terms: $6b - 3a + 6b - 2a$

Combine the terms with 'b' and the terms with 'a': $12b - 5a$

So, $3(2b-a)+2(3b-a) = 12b - 5a$.

b.) Simplifying the expression: $2a(6a-7b)-3a(5b-2a)$

Expand each term within the parentheses and then distribute 'a': $12a^2 - 14ab - 15ab + 6a^2$

Combine the 'a^2' terms and the 'ab' terms: $18a^2 - 29ab$

So, $2a(6a-7b)-3a(5b-2a) = 18a^2 - 29ab$.

c.) Simplifying the expression: $8a^{-2}a(4a-5b)$

First, simplify $8a^{-2}a$ to $8a^{-1}$: $8a^{-1}(4a-5b)$

Distribute $8a^{-1}$ into the parentheses: $32a^{-1} - 40a^{-1}b$

Since $a^{-1}$ is the same as $\frac{1}{a}$, you can rewrite the expression as: $\frac{32}{a} - \frac{40b}{a}$

So, $8a^{-2}a(4a-5b) = \frac{32}{a} - \frac{40b}{a}$.

d.) Simplifying the expression: $3(b^2 + 4b - 2) + (2+b) \cdot (-3b)$

Distribute the '3' into the parentheses and simplify the second term: $3b^2 + 12b - 6 - 3b^2$

Combine the $b^2$ terms and simplify the constants: $12b - 6$

So, $3(b^2 + 4b - 2) + (2+b) \cdot (-3b) = 12b - 6$.

Please note that '^' represents exponentiation (raising to a power) and '•' represents multiplication in your expressions. If you meant something different by these symbols, please clarify.