Question

(Х^2+х+1)(х^2+х+^2)=12

Answer 1

Ответ:

Ответ представлен на фото.

Answer 2

It seems like you have an equation involving two quadratic expressions:

$(x^2 + x + 1)(x^2 + x + 2) = 12$

To solve for the value(s) of $x$ that satisfy this equation, let's start by expanding the left-hand side of the equation:

$x^2(x^2 + x + 2) + x(x^2 + x + 2) + 1(x^2 + x + 2) = 12$

Simplify each term:

$x^4 + x^3 + 2x^2 + x^3 + x^2 + 2x + x^2 + x + 2 = 12$

Combine like terms:

$x^4 + 2x^3 + 4x^2 + 4x + 2 = 12$

Subtract 12 from both sides:

$x^4 + 2x^3 + 4x^2 + 4x - 10 = 0$

Now you have a quartic equation. Unfortunately, solving quartic equations analytically can be quite complex, and it might not have simple algebraic solutions. You might need to use numerical methods or software to find approximate solutions.

If you're looking for specific numerical solutions, you could use numerical methods like the Newton-Raphson method or tools like graphing calculators or software like Mathematica or MATLAB to find the roots of this equation.