Question

1) 5/6 + 2/7 ; 2) 11/15-3/5; 3) 3/20 + 7/15; 4) 13/16 -7/12:​

Answer 1

Пошаговое объяснение:

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Answer 2

Sure, I'd be happy to help you with those calculations:

1. $\frac{5}{6} + \frac{2}{7}$ To add these fractions, you need a common denominator, which is the least common multiple of 6 and 7, which is 42.

$$\frac{5}{6} + \frac{2}{7} = \frac{35}{42} + \frac{12}{42} = \frac{35+12}{42} = \frac{47}{42}$$

So, $\frac{5}{6} + \frac{2}{7} = \frac{47}{42}$.

2. $\frac{11}{15} - \frac{3}{5}$ Here, the denominators are already the same, so you can directly subtract the fractions.

$$\frac{11}{15} - \frac{3}{5} = \frac{11-9}{15} = \frac{2}{15}$$

So, $\frac{11}{15} - \frac{3}{5} = \frac{2}{15}$.

3. $\frac{3}{20} + \frac{7}{15}$ For this calculation, you need to find a common denominator. The least common multiple of 20 and 15 is 60.

$$\frac{3}{20} + \frac{7}{15} = \frac{9}{60} + \frac{28}{60} = \frac{9+28}{60} = \frac{37}{60}$$

So, $\frac{3}{20} + \frac{7}{15} = \frac{37}{60}$.

4. $\frac{13}{16} - \frac{7}{12}$ Again, you need a common denominator, which is the least common multiple of 16 and 12, which is 48.

$$\frac{13}{16} - \frac{7}{12} = \frac{39}{48} - \frac{28}{48} = \frac{39-28}{48} = \frac{11}{48}$$

So, $\frac{13}{16} - \frac{7}{12} = \frac{11}{48}$.

If you have any more calculations or questions, feel free to ask!