Question

1) (-2/3)² 2) -(3/4)² 3) (- 5/6)² 4) -(7/9)²​

Answer 1

Ответ:1)4/9

2)9/16

3)25/36

4)49/81

Answer 2

To find the squares of the given fractions, you simply square the numerator and the denominator separately. Let's calculate the squares of the fractions you provided:

1. $(-2/3)^2 = (-2)^2/(3)^2 = 4/9$
2. $-(3/4)^2 = -(3)^2/(4)^2 = -9/16$
3. $(-5/6)^2 = (-5)^2/(6)^2 = 25/36$
4. $-(7/9)^2 = -(7)^2/(9)^2 = -49/81$

Therefore, the squared values of the given fractions are:

1. $(-2/3)^2 = 4/9$
2. $-(3/4)^2 = -9/16$
3. $(-5/6)^2 = 25/36$
4. $-(7/9)^2 = -49/81$