Question

A) (b + c)(b-c);B) (n - m)(m + n);6) (.3 - 7)(x + 7);r) (y + 5)(5 - y);​

Answer 1

Ответ:

Пошаговое объяснение:

применим формулу a^2-b^2=(a+b)*(a-b)

a). b^2-c^2

в) (n-m)*(n+m)=n^2-m^2

б).x^2-7^2=x^2-49

г). (5+y)*(5-y)=25-y^2

Answer 2

It looks like you've provided four expressions in the form of (a + b)(a - b) or (a - b)(b + a). These expressions are special cases known as the difference of squares, and they can be simplified using the difference of squares formula, which states:

(a + b)(a - b) = a^2 - b^2

Let's apply this formula to each of your expressions:

A) (b + c)(b - c) = b^2 - c^2

B) (n - m)(m + n) = n^2 - m^2

6. (.3 - 7)(x + 7) = (.3)^2 - 7^2 = 0.09 - 49

r) (y + 5)(5 - y) = (5)^2 - (y)^2 = 25 - y^2

So, after simplifying:

A) b^2 - c^2 B) n^2 - m^2

6. -48.91 r) 25 - y^2