Question

Log25 √5 ??????????????????

Answer 1

Ответ:

$log_{25} \sqrt{5} \\\\log_{25} \sqrt{25} \\\\log_{25} (25)^{\frac{1}{2}}\\\\log_a(a^x) = x\\\\x=\frac{1}{2}$

Пошаговое объяснение:

Answer 2

To calculate the value of log base 25 of the square root of 5 (√5), you can use the logarithm properties.

log25(√5) = log25(5^(1/2))

Now, you can use the property that states log_b(a^c) = c * log_b(a):

log25(5^(1/2)) = (1/2) * log25(5)

Now, you can calculate the logarithm base 25 of 5:

log25(5) ≈ 0.4307 (approximately)

So, (1/2) * log25(5) ≈ (1/2) * 0.4307 ≈ 0.2154 (approximately)

Therefore, log25(√5) is approximately 0.2154.