Question

2(4 – y) + 2y = = –3(2x – 4) + 8 = = 6(–2a – 3) + 18 = = 5 – 2(2 – y) = =

Answer 1

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Answer 2

Let's solve each equation step by step:

1. $2(4 - y) + 2y = -3(2x - 4) + 8$

First, distribute the constants on both sides:

$8 - 2y + 2y = -6x + 12 + 8$

Now, simplify and combine like terms:

$8 = -6x + 20$

Now, isolate $x$ by moving the constants to the other side:

$-6x = 20 - 8$

$-6x = 12$

Now, divide by -6 to solve for $x$:

$x = -2$

2. $6(-2a - 3) + 18 = 5$

First, distribute the constants on the left side:

$-12a - 18 + 18 = 5$

Now, simplify and combine like terms:

$-12a = 5$

Now, isolate $a$ by moving the constants to the other side:

$-12a = 5$

Now, divide by -12 to solve for $a$:

$a = \frac{5}{-12}$

3. $5 - 2(2 - y) =$

First, simplify the expression inside the parentheses:

$5 - 2(2 - y)$

$5 - 4 + 2y$

Now, simplify the expression further:

$1 + 2y$

So, the solution to the third equation is $1 + 2y$.

If you need further clarification or have more questions, feel free to ask!