Question

(7 1/3 + 2/9 - 1 5/6) : (2 7/9 + 3 1/3 - 7/18 =​

Answer 1

Ответ:

1

Пошаговое объяснение:

Answer 2

To solve the expression (7 1/3 + 2/9 - 1 5/6) : (2 7/9 + 3 1/3 - 7/18), we'll first convert the mixed numbers into improper fractions and then perform the operations step by step.

Step 1: Convert the mixed numbers to improper fractions. 7 1/3 = 7 + 1/3 = 22/3 1 5/6 = 1 + 5/6 = 11/6 2 7/9 = 2 + 7/9 = 25/9 3 1/3 = 3 + 1/3 = 10/3

Step 2: Rewrite the expression with the improper fractions. (22/3 + 2/9 - 11/6) : (25/9 + 10/3 - 7/18)

Step 3: Perform the operations within the parentheses. Numerator of the first fraction: = (22/3 * 18/18) + (2/9 * 2/2) - (11/6 * 3/3) = (396/18) + (4/18) - (33/18)

Combine the numerators: = (396 + 4 - 33) / 18 = 367/18

Numerator of the second fraction: = (25/9 * 18/18) + (10/3 * 6/6) - (7/18 * 2/2) = (450/18) + (60/18) - (14/18)

Combine the numerators: = (450 + 60 - 14) / 18 = 496/18

Step 4: Divide the first fraction by the second fraction. = (367/18) / (496/18)

When you divide fractions, you can multiply by the reciprocal of the second fraction: = (367/18) * (18/496)

Now, you can simplify by canceling out common factors between the numerators and denominators: = (367/1) * (1/496)

= 367/496

So, (7 1/3 + 2/9 - 1 5/6) : (2 7/9 + 3 1/3 - 7/18) is equal to 367/496.