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Решите систему неравенств:{3-2(x-1)<1 3(x+3)-2(1-x)<12 Смотреть ответ Участник Знаний Участник Знаний Ответ:∅ В данной системе неравенств нет решения. Пошаговое объяснение: Новые вопросы в Математика Напечататанный принтером файл содержит 48 страниц. 2/3 файла занимает текст, 2/9- фотографии, а остальные - рисунки. Сколько страниц файла занимают ри … сунки?​ ПОЖАЛУЙСТА ПОМОГИТЕ ДАЮ 30 БАЛЛОВ! Брати богдан і борис напередодні навчального року купили 26 зошитів у клітинку по 45 к 16 зошитів у лінійку по 60 к … та декілька ручок по 1 грн 20 к. За всю покупку брати заплатили 29,7 грн. Скільки ручок купили хлопці? З пункту А в пункт В авто їде зі швидкістю 50 км/год. Назад вертається з В в А зі шв. 30 км/год. ЯКА СЕРЕДНЯ ШВИДКІСТЬ АВТО ? Відповідь не 40!!!​ Яка із зображених на рисунку прямих паралельна прямій АВ ? ПОЖАЛУЙСТА ПОМОГИТЕ ДАЮ 20 БАЛОВ ​ Яка із зображених на рисунку прямих перпендикулярна до прямої АВ ? ПОЖАЛУЙСТА ТОЧНЫЙ ОТВЕТ!! 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Answer 1

Давайте решим систему неравенств поочередно:

1. Начнем с первого неравенства: $3 - 2(x-1) < 1$

   Раскроем скобки: $3 - 2x + 2 < 1$

   Упростим: $5 - 2x < 1$

   Теперь выразим $x$: $-2x < 1 - 5$

   $-2x < -4$

   Теперь разделим обе стороны на -2, помните, что при делении на отрицательное число неравенство меняет знак: $x > 2$

2. Теперь перейдем ко второму неравенству: $3(x+3) - 2(1-x) < 12$

   Раскроем скобки: $3x + 9 - 2 + 2x < 12$

   Упростим: $5x + 7 < 12$

   Теперь выразим $x$: $5x < 12 - 7$

   $5x < 5$

   Разделим обе стороны на 5: $x < 1$

Итак, мы получили два решения:

1. $x > 2$
2. $x < 1$

Чтобы найти общее решение системы неравенств, найдем их пересечение:

Из $x > 2$ и $x < 1$ видно, что нет общего решения, потому что нельзя одновременно удовлетворить оба условия. Таким образом, решениями данной системы неравенств является пустое множество ($\emptyset$), что совпадает с вашим ответом.