Question

1) 13х > 65; 2) – 4x ≥ 40; 3) -3x < -21 ; 4) 0,2x>3,4; 5) 4 – x > 3x + 12; 6) x – 15 < 2x – 2; 7) 16 + x≤ 4x - 2; 8) – 3х-4 ≤ 5 + 6x

Answer 1

Ответ:это какай класс

Пошаговое объяснение:

Answer 2

To solve these inequalities for the variable x, follow these steps:

1. 13x > 65 Divide both sides by 13 to isolate x: x > 65/13 x > 5

2. -4x ≥ 40 Divide both sides by -4, but remember to reverse the inequality when dividing by a negative number: x ≤ 40 / -4 x ≤ -10

3. -3x < -21 Divide both sides by -3, and remember to reverse the inequality when dividing by a negative number: x > -21 / -3 x > 7

4. 0.2x > 3.4 Divide both sides by 0.2 to isolate x: x > 3.4 / 0.2 x > 17

5. 4 - x > 3x + 12 Add x to both sides: 4 > 4x + 12 Subtract 12 from both sides: -8 > 4x Divide both sides by 4, but remember to reverse the inequality when dividing by a negative number: x < -2

6. x - 15 < 2x - 2 Subtract x from both sides: -15 < x - 2 Add 2 to both sides: -13 < x

7. 16 + x ≤ 4x - 2 Subtract x from both sides: 16 ≤ 3x - 2 Add 2 to both sides: 18 ≤ 3x Divide both sides by 3: 6 ≤ x

8. -3x - 4 ≤ 5 + 6x Add 4 to both sides: -3x ≤ 9 + 6x Subtract 6x from both sides: -9x ≤ 9 Divide both sides by -9, but remember to reverse the inequality when dividing by a negative number: x ≥ -1

So, the solutions to the inequalities are:

1. x > 5
2. x ≤ -10
3. x > 7
4. x > 17
5. x < -2
6. x > -13
7. x ≥ 6
8. x ≥ -1