Question

2) 2(y-2) > 3y +1, 5(y + 1) < 4y + 3;4) 2(3x + 2) > 5(x - 1),17(x + 2) < 3(2x + 3).​

Answer 1

Ответ:

1) 2(у-2)>3у+1

2у-3у>1+4

у<-5

2) (у+1)<4у+3

у-4у<3-1

-3у<2

у> -2/3

3) 2(3х+2)>5(х-1)

6х-5х>-5-4

х>-9

4) 17(х+2)< 3(2х+3)

17х-6х< 9-34

11х<-25

х<-25/11

надеюсь помог

Answer 2

Let's solve each of these inequalities step by step:

1. 2(y - 2) > 3y + 1

First, distribute the 2 on the left side of the inequality:

2y - 4 > 3y + 1

Next, move all the y terms to one side of the inequality and the constant terms to the other side:

2y - 3y > 1 + 4

-y > 5

Now, multiply both sides by -1 to reverse the inequality sign (remember to reverse the sign when multiplying by a negative number):

y < -5

So, the solution for this inequality is y < -5.

2. 5(y + 1) < 4y + 3

First, distribute the 5 on the left side of the inequality:

5y + 5 < 4y + 3

Next, move all the y terms to one side of the inequality and the constant terms to the other side:

5y - 4y < 3 - 5

y < -2

So, the solution for this inequality is y < -2.

3. 2(3x + 2) > 5(x - 1)

First, distribute the 2 on the left side and the 5 on the right side of the inequality:

6x + 4 > 5x - 5

Next, move all the x terms to one side of the inequality and the constant terms to the other side:

6x - 5x > -5 - 4

x > -9

So, the solution for this inequality is x > -9.

4. 17(x + 2) < 3(2x + 3)

First, distribute the 17 on the left side and the 3 on the right side of the inequality:

17x + 34 < 6x + 9

Next, move all the x terms to one side of the inequality and the constant terms to the other side:

17x - 6x < 9 - 34

11x < -25

Now, divide both sides by 11:

x < -25/11

So, the solution for this inequality is x < -25/11.