Question

4) 2(3x + 2) > 5(x - 1),7(x + 2) <3(2x + 3).​

Answer 1

2(3х+2)>5(х-1)

6х+4>5х-5

6х-5х>-5-4

х>-9

7(х+2)<3(2х+3)

7х+14<6х+9

7х-6х<9-14

х<-5

Answer 2

To solve this system of inequalities:

1. Let's start with the first inequality: 2(3x + 2) > 5(x - 1)

   First, distribute the constants inside the parentheses: 6x + 4 > 5x - 5

   Now, move all terms containing x to the left side and constants to the right side: 6x - 5x > -5 - 4

   Simplify the left side: x > -9

2. Now, let's move on to the second inequality: 7(x + 2) < 3(2x + 3)

   First, distribute the constants inside the parentheses: 7x + 14 < 6x + 9

   Move all terms containing x to the left side and constants to the right side: 7x - 6x < 9 - 14

   Simplify the left side: x < -5

Now, you have the solutions for both inequalities:

1. For the first inequality, x > -9.
2. For the second inequality, x < -5.

So, the solution to the system of inequalities is:

-9 < x < -5