Question

1)1 3/8-3 1/42)-2 14/15-1 19/453)-3 1/6-(-1 1/4)​

Answer 1

Ответ:

1)11/8-13/4= -15/8= -1 7/8

2)-((2+1))+(14/5+19/45)= -(3+61/45)= -(3+1 16/45)= -(4+16/45)= -4 16/45

3)-19/6+5/4= -23/12= -1 11/12

Answer 2

Let's solve each of these subtraction problems step by step:

1. $1 \frac{3}{8} - 3 \frac{1}{4}$

To subtract mixed numbers, first subtract the whole numbers and then subtract the fractions.

Whole numbers: $1 - 3 = -2$

Now, subtract the fractions:

$\frac{3}{8} - \frac{1}{4}$

To subtract these fractions, we need a common denominator. The least common denominator for 8 and 4 is 8. So, we'll convert both fractions to have a denominator of 8:

$\frac{3}{8} - \frac{2}{8}$

Now, subtract the fractions:

$\frac{3 - 2}{8} = \frac{1}{8}$

So, $1 \frac{3}{8} - 3 \frac{1}{4} = -2 \frac{1}{8}$

2. $2 \frac{14}{15} - 1 \frac{19}{45}$

First, subtract the whole numbers:

$2 - 1 = 1$

Now, subtract the fractions:

$\frac{14}{15} - \frac{19}{45}$

To subtract these fractions, we need a common denominator. The least common denominator for 15 and 45 is 45. So, we'll convert both fractions to have a denominator of 45:

$\frac{14}{15} - \frac{19}{45}$

Now, subtract the fractions:

$\frac{14 \cdot 3}{15 \cdot 3} - \frac{19}{45} = \frac{42}{45} - \frac{19}{45}$

Now, subtract the fractions:

$\frac{42 - 19}{45} = \frac{23}{45}$

So, $2 \frac{14}{15} - 1 \frac{19}{45} = 1 \frac{23}{45}$

3. $3 \frac{1}{6} - (-1 \frac{1}{4})$

To subtract a negative number, change the subtraction to addition and change the sign of the number being subtracted:

$3 \frac{1}{6} + 1 \frac{1}{4}$

Now, add the whole numbers:

$3 + 1 = 4$

Now, add the fractions:

$\frac{1}{6} + \frac{1}{4}$

To add these fractions, we need a common denominator. The least common denominator for 6 and 4 is 12. So, we'll convert both fractions to have a denominator of 12:

$\frac{1}{6} + \frac{1}{4} = \frac{2}{12} + \frac{3}{12}$

Now, add the fractions:

$\frac{2 + 3}{12} = \frac{5}{12}$

So, $3 \frac{1}{6} - (-1 \frac{1}{4}) = 4 \frac{5}{12}$