Question

2 1/3 :(5/8-8/3) -2* 1 3/7

Answer 1

$2 \frac{1}{3} \div ( \frac{5}{8} - \frac{8}{3} ) - 2 \times 1 \frac{3}{7} = - 2 \\ proverka \\ \frac{7}{3} \div ( - \frac{49}{24} ) - \frac{6}{7} \\ - \frac{7}{3} \times \frac{24}{49} - \frac{6}{7} \\ - \frac{8}{7} - \frac{6}{7} \\ - 2$

Answer 2

To solve the given expression, let's break it down step by step:

1. Evaluate the expressions inside parentheses: $\frac{5}{8} - \frac{8}{3}$

To subtract these fractions, we need a common denominator, which is 24. So:

$\frac{15}{24} - \frac{64}{24} = \frac{-49}{24}$

2. Substitute the result back into the original expression:

$2\frac{1}{3} : \left(\frac{-49}{24}\right) - 2\frac{1}{7}$

3. Convert mixed numbers to improper fractions: $2\frac{1}{3} = \frac{7}{3}$ and $2\frac{1}{7} = \frac{15}{7}$

4. Divide by a fraction is the same as multiplying by its reciprocal:

$\frac{7}{3} \div \frac{-49}{24} = \frac{7}{3} \times \left(-\frac{24}{49}\right) = -\frac{8}{7}$

5. Substitute this result back into the expression:

$-\frac{8}{7} - \frac{15}{7}$

6. Subtract the fractions:

$-\frac{8}{7} - \frac{15}{7} = -\frac{23}{7}$

So, the final result of the given expression is $-\frac{23}{7}$.