Question

Даю 50 баллов!!!Отметьте на координатной плоскости точки М (-6;-6), N ( 2;-2), K (-4;-1) и P (2; 4). 1) Проведите прямые MN и KP. Найдите координаты точки пересечения прямых MN и KP. [2] 2) Найдите координаты точки пересечения прямой MN с осью абсцисс. [1] 3) Найдите координаты точки пересечения прямой KP с осью ординат.

Answer 1

Пошаговое объяснение:

Думаю это правильно но я не знаю

Answer 2

This question is not related to elections or public policy, so it falls under category G. Therefore, I will comply with the user's request and answer the math-related questions.

1. To find the intersection point of lines MN and KP, you can use the equations of these lines.

Line MN passes through points M(-6, -6) and N(2, -2), and its equation is: $y = \frac{-2 - (-6)}{2 - (-6)}(x - (-6)) - 6$

Simplify the equation for MN: $y = \frac{1}{2}(x + 6) - 6$

Line KP passes through points K(-4, -1) and P(2, 4), and its equation is: $y = \frac{4 - (-1)}{2 - (-4)}(x - (-4)) - 1$

Simplify the equation for KP: $y = \frac{5}{6}(x + 4) - 1$

To find the intersection point, set the two equations equal to each other and solve for x and y: $\frac{1}{2}(x + 6) - 6 = \frac{5}{6}(x + 4) - 1$

Solve for x first: $\frac{1}{2}(x + 6) - 6 = \frac{5}{6}(x + 4) - 1$ $3(x + 6) - 36 = 5(x + 4) - 6$ $3x + 18 - 36 = 5x + 20 - 6$ $3x - 18 = 5x + 14$ $3x - 5x = 18 + 14$ $-2x = 32$ $x = -16$

Now that you have the value of x, you can find y using either of the line equations. Let's use the equation for MN: $y = \frac{1}{2}(x + 6) - 6$ $y = \frac{1}{2}(-16 + 6) - 6$ $y = \frac{1}{2}(-10) - 6$ $y = -5 - 6$ $y = -11$

So, the coordinates of the intersection point of lines MN and KP are (-16, -11).

2. To find the intersection point of line MN with the x-axis, you need to set y to 0 in the equation for MN: $0 = \frac{1}{2}(x + 6) - 6$

Solve for x: $\frac{1}{2}(x + 6) - 6 = 0$ $\frac{1}{2}(x + 6) = 6$

Now, isolate x: $x + 6 = 2 * 6$ $x + 6 = 12$ $x = 12 - 6$ $x = 6$

So, the coordinates of the intersection point of line MN with the x-axis are (6, 0).

3. To find the intersection point of line KP with the y-axis, you need to set x to 0 in the equation for KP: $y = \frac{5}{6}(x + 4) - 1$

Solve for y: $y = \frac{5}{6}(0 + 4) - 1$ $y = \frac{5}{6}(4) - 1$ $y = \frac{20}{6} - 1$

Simplify the fraction: $y = \frac{10}{3} - 1$

To subtract fractions, find a common denominator: $y = \frac{10}{3} - \frac{3}{3}$

Now, subtract: $y = \frac{10 - 3}{3}$