
2) y = -3(x - 2)2 + 7;


Ответы на вопрос

Ответ:
y=2(-3x+6)+7
y=-6x+12+7
y+6x=19
Пошаговое объяснение:
кажется вы ошиблись, когда написали задачу



The equation you provided is a quadratic equation in the form of y = ax^2 + bx + c. In this case, the equation is already in vertex form, which is a useful form to understand the vertex and other characteristics of the quadratic function.
Here's the equation you provided:
y = -3(x - 2)^2 + 7
In this equation:
- "a" is the coefficient of the squared term, which is -3.
- (h, k) represents the vertex of the parabola, where (h, k) = (2, 7) in this case.
The vertex form of a quadratic equation is:
y = a(x - h)^2 + k
In your equation, h = 2 and k = 7, so the vertex of the parabola is at (2, 7). The value of "a" (the coefficient of the squared term) tells you whether the parabola opens upward (if a is positive) or downward (if a is negative).
In your equation, since "a" is -3, the parabola opens downward.
So, this quadratic function is a downward-facing parabola with its vertex at (2, 7), and it's stretched or compressed vertically by a factor of 3. This means it's narrower and steeper compared to the standard quadratic function y = x^2.
If you have any specific questions about this equation or need further assistance, please let me know!


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