Question

1) 2(x-3) = 362) 4(5-х) = 123) 0,1(х+1) = 1​

Answer 1

Відповідь:

Покрокове пояснення:

Answer 2

To solve these equations, you can follow these steps:

1. 2(x-3) = 36

First, distribute the 2 on the left side of the equation:

2x - 6 = 36

Now, add 6 to both sides to isolate the variable term:

2x = 36 + 6 2x = 42

Finally, divide both sides by 2 to solve for x:

x = 42 / 2 x = 21

So, the solution is x = 21.

2. 4(5-x) = 12

First, distribute the 4 on the left side of the equation:

20 - 4x = 12

Now, subtract 20 from both sides to isolate the variable term:

-4x = 12 - 20 -4x = -8

Finally, divide both sides by -4 to solve for x:

x = (-8) / (-4) x = 2

So, the solution is x = 2.

3. 0.1(x+1) = 1

First, distribute the 0.1 on the left side of the equation:

0.1x + 0.1 = 1

Now, subtract 0.1 from both sides to isolate the variable term:

0.1x = 1 - 0.1 0.1x = 0.9

Finally, divide both sides by 0.1 to solve for x:

x = 0.9 / 0.1 x = 9

So, the solution is x = 9.