Question

2-х=3х+6 2(3х-4)=4 4(х-3)=0 8х=-16

Answer 1

$1) 2-x=3x+6\\2-x-2=3x+6-2\\-x=3x+4\\-x-3x=3x+4-3x\\-4x=4\\\frac{-4x}{-4}=\frac{4}{-4}\\x=-1$

$2) 2\left(3x-4\right)=4\\\frac{2\left(3x-4\right)}{2}=\frac{4}{2}\\3x-4=2\\3x-4+4=2+4\\3x=6\\\frac{3x}{3}=\frac{6}{3}\\x=2$

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Answer 2

Let's solve the equations step by step:

1. 2x = 3x + 6 First, subtract 3x from both sides to isolate x: 2x - 3x = 3x - 3x + 6 -x = 6 Now, multiply both sides by -1 to solve for x: -1 * (-x) = -1 * 6 x = -6

2. 2(3x - 4) = 4 Distribute the 2 on the left side of the equation: 6x - 8 = 4 Add 8 to both sides to isolate 6x: 6x - 8 + 8 = 4 + 8 6x = 12 Now, divide both sides by 6 to solve for x: (6x)/6 = 12/6 x = 2

3. 4(x - 3) = 0 Distribute the 4 on the left side of the equation: 4x - 12 = 0 Add 12 to both sides to isolate 4x: 4x - 12 + 12 = 0 + 12 4x = 12 Now, divide both sides by 4 to solve for x: (4x)/4 = 12/4 x = 3

4. 8x = -16 Divide both sides by 8 to isolate x: (8x)/8 = (-16)/8 x = -2

So, the solutions to the given equations are:

1. x = -6
2. x = 2
3. x = 3
4. x = -2