Question

3х(х-2)-х(3+х)=2(х-4)-4​

Answer 1

Ответ:

3х(х-2)-х(3+х)=2(х-4)-4

3х²-6х-3х-х²=2х-8-4

2х²-9х=2х-12

2х²-11х=-12

2х²-11х+12=0

D=(-11)²-4×2×12=121-96=25

x1=(11+√25)/(2×2)=(11+5)/4=16/4=4

x2=(11-√25)/(2×2)=(11-5)/4=6/4=1,5

Ответ:х1=4 х2=1,5

можно пожалуйста лучший ответ

Answer 2

To solve the equation 3x(x-2) - x(3+x) = 2(x-4) - 4, you can follow these steps:

1. Distribute the terms on both sides of the equation: 3x(x) - 3x(2) - x(3) - x(x) = 2(x) - 2(4) - 4

2. Simplify the equation by multiplying and combining like terms: 3x^2 - 6x - 3x^2 - x^2 = 2x - 8 - 4

3. Continue simplifying the equation: (3x^2 - 6x - 3x^2 - x^2) = 2x - 12

4. Combine like terms on both sides of the equation: -4x^2 - 6x = 2x - 12

5. Add 4x^2 and 6x to both sides to isolate the x terms on one side: -4x^2 - 6x + 4x^2 + 6x = 2x - 12 + 4x^2 + 6x

6. Simplify further: 0 = 2x^2 - 12

7. Divide both sides of the equation by 2 to solve for x: 0/2 = (2x^2 - 12)/2

8. Simplify: 0 = x^2 - 6

9. Add 6 to both sides to isolate x^2: 6 = x^2

10. Take the square root of both sides: ±√6 = x

So, the solutions to the equation are: x = √6 and x = -√6.