Question

Y=x^4-2x^2 y(x)= y(-1)= y(0)= y(2)=

Answer 1

Ответ:

нужно просто подставлять значения

y (x) = x^4-2x^2

у (-1) = (-1)^4-2(-1)^2=1-2= -1

у (0) = 0- 2×0=0

у (2) = 2^4-2×2^2= 16-2×4=8

Answer 2

To find the values of y(-1), y(0), and y(2) for the given function y(x) = x^4 - 2x^2, we simply substitute the respective values of x into the function and compute y(x).

1. y(-1): $y(-1) = (-1)^4 - 2(-1)^2 = 1 - 2 = -1$

2. y(0): $y(0) = 0^4 - 2(0)^2 = 0$

3. y(2): $y(2) = 2^4 - 2(2)^2 = 16 - 8 = 8$

So, the values of y(-1), y(0), and y(2) are: $y(-1) = -1, \quad y(0) = 0, \quad y(2) = 8$