Question

6х +y=174х +3y = 23​

Answer 1

Ответ:

(2;5)

Пошаговое объяснение:

из первого выразим ИГРИК и сразу подставим во второе:

$\left \{ {{y=17-6x} \atop {4x+3(17-6x)=23} \right.$

$\left \{ {{y=17-6x} \atop {4x+51-18x=23} \right.$

$\left \{ {{y=17-6x} \atop {-14x=-28}} \right.$

вычислим ИКС и подставим в первое

$\left \{ {{y=17-6*2} \atop {x=2}} \right.$

$\left \{ {{y=5} \atop {x=2}} \right.$

Answer 2

It appears that you have a system of two linear equations with two variables, x and y. To solve for the values of x and y that satisfy both equations, you can use the method of substitution or elimination. Let's use the elimination method:

1. 6x + y = 17
2. 3x + 3y = 23

First, let's make the coefficients of y in both equations equal so that we can eliminate y. We can do this by multiplying the first equation by 3:

1. 18x + 3y = 51
2. 3x + 3y = 23

Now, you can subtract the second equation from the first equation to eliminate y:

(18x + 3y) - (3x + 3y) = 51 - 23

This simplifies to:

15x = 28

Now, divide both sides by 15 to isolate x:

x = 28/15

Now that you have found the value of x, you can substitute it back into either of the original equations to solve for y. Let's use the first equation:

6x + y = 17 6(28/15) + y = 17

Now, solve for y:

y = 17 - 6(28/15)

To simplify further:

y = 17 - (56/15)

To get a common denominator:

y = (255/15) - (56/15)

Now subtract:

y = (199/15)

So, the solution to the system of equations is:

x = 28/15 y = 199/15