Question

1) (x^2-2)'=2) (x-6)'=3) (25)'=​

Answer 1

$1) \left(x^2-2\right)'\:$

$=\left(x^2\right)'\:-2'\:$

$=2x-0$

$=2x$

ответь:

$=2x$

$2) \left(x-6\right)'\:$

$=x'\:-6'\:$

$=1-0$

$=1$

ответь:

$=1$

$3) (25)'$

$25'\:$

$=0$

ответь:

$=0$

Answer 2

1. To find the derivative of (x^2 - 2) with respect to x, you can apply the power rule. The power rule states that if you have a term of the form x^n, its derivative is nx^(n-1).

So, for (x^2 - 2):

d/dx (x^2 - 2) = 2x^1 - 0 (since the derivative of a constant like -2 is 0) d/dx (x^2 - 2) = 2x

2. To find the derivative of (x - 6), you can again apply the power rule. Here, it's a linear term, so the derivative is simply 1.

d/dx (x - 6) = 1

3. The derivative of a constant, like 25, is always 0.

d/dx (25) = 0

So, to summarize:

1. (x^2 - 2)' = 2x
2. (x - 6)' = 1
3. (25)' = 0