Question

0,2x-4y=2.а) 0,5x + 2y=11​

Answer 1

Ответ:

Умножаем второе уравнение на 2, получам

0,2х-4у=2

х+4у=22

Складываем оба уравнения

1.2х=24

х=24/1,2

х=20

Подставим значение х=20 в уравнение х+4у=22

20+4у=22

4у=2

у=0,5

Ответ (20; 0,5)

Пошаговое объяснение:

Answer 2

To solve the system of equations:

1. 0.2x - 4y = 2
2. 0.5x + 2y = 11

You can use the method of substitution or elimination. I'll use the elimination method in this case.

First, let's multiply both sides of the first equation by 5 to make it easier to eliminate one of the variables:

1. 5(0.2x - 4y) = 5(2) 1x - 20y = 10

Now, the system becomes:

1. x - 20y = 10
2. 0.5x + 2y = 11

To eliminate one of the variables (in this case, I'll eliminate x), you can multiply the second equation by 2 to make the coefficients of x in both equations equal:

1. x - 20y = 10
2. x + 4y = 22

Now, subtract the second equation from the first equation to eliminate x:

(x - 20y) - (x + 4y) = 10 - 22

Simplify:

x - 20y - x - 4y = -12

Now, combine like terms:

-24y = -12

Divide by -24 to solve for y:

y = -12 / -24 y = 1/2

Now that you have found the value of y, substitute it back into one of the original equations to solve for x. Let's use the first equation:

0.2x - 4(1/2) = 2

0.2x - 2 = 2

Add 2 to both sides:

0.2x = 4

Now, divide by 0.2 to solve for x:

x = 4 / 0.2 x = 20

So, the solution to the system of equations is:

x = 20 y = 1/2