Question

(a+a-b\a+b-b):(2a+1/a2-b2+1)​

Answer 1

Ответ:

Пошаговое объяснение:

(a+b/a^2-ab-1/a):b/b-a

a(b/a-b-1):b/b-a (a-сокращаем)

(b/a-b-1):b/b

1) b-ab-a=b-ab

       a

2) b-ab:b/b=ab(умноженная) b

3)0.5(умножен)7-2(умножен)7-2= -12,5

ответ: -12,5

Answer 2

It appears you're trying to simplify the expression:

(a + a - b) / (a + b - b) : (2a + 1 / (a^2 - b^2 + 1))

Let's simplify this step by step:

1. Combine like terms in the numerators:

   (2a - b) / (a) : (2a + 1 / (a^2 - b^2 + 1))

2. Factor the denominator in the second fraction:

   (2a - b) / a : (2a + 1 / ((a + b)(a - b) + 1))

3. The denominators in both fractions have a common factor of 'a.' So, you can cancel out 'a' from both denominators:

   (2 - (b / a)) : (2 + 1 / ((a + b)(a - b) + 1))

4. Now, you have the simplified expression:

   (2 - (b / a)) : (2 + 1 / ((a + b)(a - b) + 1))

This is the simplified expression, and you can't simplify it further without specific values for 'a' and 'b'.