Question

2(х-4)-3(2х+1) = 17-5х

Answer 1

Ответ:

Пошаговое объяснение:

2(х-4)-3(2х+1) = 17-5х

2x - 8 - 6x - 3 = 17 - 5x

-4x - 11 = 17 - 5x

5x - 4x = 17 + 11

x = 28

Answer 2

Відповідь:

2(x-4) - 3(2x+1) = 17- 5x

2x - 8 - 6x -1 = 17 - 5x

2x - 6x + 5x = 17 + 8 - 1

-4x + 5x

1x = 24

x = 24 : 1

x = 24

Answer 3

To solve the equation 2(x-4) - 3(2x+1) = 17 - 5x, you can follow these steps:

1. Distribute the constants outside the parentheses to the terms inside the parentheses:

2(x) - 2(4) - 3(2x) - 3(1) = 17 - 5x

This simplifies to:

2x - 8 - 6x - 3 = 17 - 5x

2. Combine like terms on both sides of the equation. Group the x terms on one side and the constants on the other side:

(2x - 6x + 5x) - 8 - 3 = 17

This simplifies to:

-1x - 11 = 17

3. Now, isolate the variable x by adding 11 to both sides of the equation to get rid of the -11 on the left side:

-1x - 11 + 11 = 17 + 11

This simplifies to:

-1x = 28

4. Finally, divide both sides of the equation by -1 to solve for x:

x = 28 / -1

x = -28

So, the solution to the equation 2(x-4) - 3(2x+1) = 17 - 5x is x = -28.