Question

1) 2,5/7y = 5/42 2) 9,3/15 = 3,1/4y 3) 169/100 = 13/2y 4) 5,7/20 = 0,5y/40​

Answer 1

Ответ:

1) 2,5/7y = 5/42

2,5/5 = 7y/42

0,5=7y/42

21=7y

y=3

2)9,3/15=3,1/4y

9,3/3,1=15/4y

4y=15/-3

4y=-5

y=-1 4/5

Answer 2

To solve each of these equations for "y," you can follow these steps:

1. 2,5/7y = 5/42

First, isolate "y" by multiplying both sides of the equation by the reciprocal of 2,5/7, which is 7/2, to get:

y = (5/42) * (7/2)

y = (5/6) * (1/6)

y = 5/36

2. 9,3/15 = 3,1/4y

First, subtract 9,3/15 from both sides of the equation to isolate the term with "y" on the right side:

3,1/4y = 9,3/15 - 9,3/15

3,1/4y = 0

Now, divide both sides by 3,1/4 to solve for "y":

y = 0 / (3,1/4)

y = 0

3. 169/100 = 13/2y

To solve for "y," first multiply both sides of the equation by the reciprocal of 13/2, which is 2/13:

y = (169/100) * (2/13)

y = (338/1300)

y = (169/650)

4. 5,7/20 = 0,5y/40

To solve for "y," first multiply both sides of the equation by 40 to get rid of the denominator on the right side:

40 * (5,7/20) = 0,5y

Now, simplify the left side:

(5,7/20) * 40 = 2 * 5,7 = 11,4

So the equation becomes:

11,4 = 0,5y

Now, divide both sides by 0,5 to solve for "y":

y = 11,4 / 0,5

y = 22.8