Question

(х-7)(3х-2)-(5х+1)(2х-4)​

Answer 1

Ответ:

$(x - 7)(3x - 2) - (5x + 1)(2x - 4) = {3x}^{2} - 2x - 21x + 14 - ( {10x}^{2} - 20x + 2x - 4) = {3x}^{2} - 2x - 21x + 14 - ( {10x}^{2} - 18x - 4) = {3x}^{2} - 2x - 21x + 14 - {10x}^{2} + 18x + 4 = { - 7x}^{2} - 5x + 18$

Answer 2

To simplify the expression (x-7)(3x-2) - (5x+1)(2x-4), you can use the distributive property to expand the products and then combine like terms:

(x-7)(3x-2) - (5x+1)(2x-4)

First, let's expand the products within each set of parentheses:

(x-7)(3x-2) = x(3x) - x(2) - 7(3x) + 7(2) = 3x^2 - 2x - 21x + 14

(5x+1)(2x-4) = 5x(2x) - 5x(4) + 1(2x) - 1(4) = 10x^2 - 20x + 2x - 4

Now, let's combine like terms within each set of parentheses:

3x^2 - 2x - 21x + 14 = 3x^2 - 23x + 14

10x^2 - 20x + 2x - 4 = 10x^2 - 18x - 4

Now, we can subtract the second expression from the first:

(3x^2 - 23x + 14) - (10x^2 - 18x - 4)

To subtract, distribute the negative sign to all terms in the second expression:

3x^2 - 23x + 14 - 10x^2 + 18x + 4

Now, combine like terms:

(3x^2 - 10x^2) + (-23x + 18x) + (14 + 4)

-7x^2 - 5x + 18

So, the simplified expression is -7x^2 - 5x + 18.