Question

Расстояние между А и В по шоссе равно 111 км. Между ними в 19 км от в расположен пункт С. Из А в В выезжает автомобиль и одновременно из BA- велосипедист. Через час после выезда автомобиль был вдвое ближе к С, чем велосипедист. Еще через минут велосипедист был в два раза ближе к С, чем автомобиль. Какова скорость автомобиля?

Answer 1

Ответ:

Скорость автомобиля = 11

Answer 2

Problem Analysis

We are given that the distance between points A and B on a highway is 111 km. Point C is located 19 km from point A. An automobile and a bicyclist simultaneously start from points A and B, respectively. After one hour, the automobile is twice as close to point C as the bicyclist. After a few minutes, the bicyclist is twice as close to point C as the automobile. We need to determine the speed of the automobile.

Solution

Let's assume the speed of the automobile is x km/h. Since the automobile is twice as close to point C as the bicyclist after one hour, we can set up the following equation:

Distance covered by the automobile in one hour = 2 * Distance covered by the bicyclist in one hour

The distance covered by the automobile in one hour is x km, and the distance covered by the bicyclist in one hour is x - 19 km. Therefore, we have:

x = 2 * (x - 19)

Simplifying the equation:

x = 2x - 38

38 = x

Therefore, the speed of the automobile is 38 km/h.

Answer

The speed of the automobile is 38 km/h.